4x^2+32x-5=-5

Solution for 4x^2+32x-5=-5 equation:

4x^2+32x-5=-5

We move all terms to the left:

4x^2+32x-5-(-5)=0

We add all the numbers together, and all the variables

4x^2+32x=0

a = 4; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·4·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*4}=\frac{0}{8}
=0
$